Match the LIST-I (Letter-series) with LIST-II (Missing letter):

LIST-I		LIST-II
A. Q, N, K, H, E, ?		I. C
B. O, B, L, ?, I, D, F, C		II. K
C. Z, U, Q, N, L, ?		III. B
D. A, C, ?, G, I		IV. E

Choose the correct answer from the options given below:LIST-I (अक्षर-शृंखला) का LIST-II (लुप्त अक्षर) से मिलान कीजिए:

LIST-I		LIST-II
A. Q, N, K, H, E, ?		I. C
B. O, B, L, ?, I, D, F, C		II. K
C. Z, U, Q, N, L, ?		III. B
D. A, C, ?, G, I		IV. E

नीचे दिए गए विकल्पों में से सही उत्तर चुनिए:

1. AA-I, B-II, C-III, D-IV
2. BA-III, B-I, C-IV, D-II
3. CA-I, B-II, C-IV, D-III
4. DA-III, B-I, C-II, D-IV

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: D. A-III, B-I, C-II, D-IV

Explanation

A: Q(17),N(14),K(11),H(8),E(5) decreases by 3 each time, so next = 2 = B → III. C: Z(26),U(21),Q(17),N(14),L(12) decreases by 5,4,3,2, so next = 12-1 = 11 = K → II. D: A(1),C(3),?,G(7),I(9) increases by 2 each time, so missing = 5 = E → IV. By elimination, B's missing letter must be the remaining choice, C → I. So A-III, B-I, C-II, D-IV.A: Q(17),N(14),K(11),H(8),E(5) प्रत्येक बार 3 घटता है, अतः अगला = 2 = B → III। C: Z(26),U(21),Q(17),N(14),L(12) 5,4,3,2 घटता है, अतः अगला = 12-1 = 11 = K → II। D: A(1),C(3),?,G(7),I(9) प्रत्येक बार 2 बढ़ता है, अतः लुप्त = 5 = E → IV। हटाने की प्रक्रिया से, B का लुप्त अक्षर शेष विकल्प, C → I होना चाहिए। अतः A-III, B-I, C-II, D-IV।