Match the LIST-I with LIST-II

LIST-I (Question)	LIST-II (Answer)
A. If x + 1/x = 2, then (x − 1/x) = ?	I. 11
B. If x − y = 1 and x² + y² = 41, then x + y = ?	II. 2
C. If (1 − 1/x) = 2, then 1 + 1/x² = ?	III. 0
D. If (x − 1/x) = 3, then x² + 1/x² = ?	IV. ± 9

Choose the correct answer from the options given below:सूची-I का सूची-II के साथ मिलान कीजिए

सूची-I (प्रश्न)	सूची-II (उत्तर)
A. यदि x + 1/x = 2, तो (x − 1/x) = ?	I. 11
B. यदि x − y = 1 और x² + y² = 41, तो x + y = ?	II. 2
C. यदि (1 − 1/x) = 2, तो 1 + 1/x² = ?	III. 0
D. यदि (x − 1/x) = 3, तो x² + 1/x² = ?	IV. ± 9

नीचे दिए गए विकल्पों में से सही उत्तर चुनिए:

1. AA-I, B-III, C-IV, D-II
2. BA-I, B-II, C-III, D-IV
3. CA-II, B-III, C-I, D-IV
4. DA-III, B-IV, C-II, D-I

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: D. A-III, B-IV, C-II, D-I

Explanation

A: x + 1/x = 2 gives x = 1, so x − 1/x = 0 (III). B: (x + y)² = 2(x² + y²) − (x − y)² = 2(41) − 1 = 81, so x + y = ± 9 (IV). C: 1 − 1/x = 2 gives 1/x = −1, so 1 + 1/x² = 1 + 1 = 2 (II). D: (x − 1/x)² = x² + 1/x² − 2, so x² + 1/x² = 9 + 2 = 11 (I). Hence A-III, B-IV, C-II, D-I.A: x + 1/x = 2 से x = 1, अतः x − 1/x = 0 (III)। B: (x + y)² = 2(x² + y²) − (x − y)² = 2(41) − 1 = 81, अतः x + y = ± 9 (IV)। C: 1 − 1/x = 2 से 1/x = −1, अतः 1 + 1/x² = 1 + 1 = 2 (II)। D: (x − 1/x)² = x² + 1/x² − 2, अतः x² + 1/x² = 9 + 2 = 11 (I)। अतः A-III, B-IV, C-II, D-I।