Match List - I with List - II:

List - I	List - II
A. The numerator of a fraction is increased by 25% and the denominator is increased by 50% leading to a value of 5/3. The original fraction is ______	I. 1/10
B. 4⅓ − 3½ = ______	II. 2/5
C. The fraction equivalent to 40% is ______	III. 5/6
D. 0.064 ÷ (3.25 × 3.20 − 3.20 × 3.05)	IV. 2/1

Choose the correct answer from the options given below:सूची - I को सूची - II से सुमेलित कीजिए:

सूची - I	सूची - II
A. एक भिन्न का अंश 25% बढ़ाया जाता है और हर 50% बढ़ाया जाता है, जिससे मान 5/3 हो जाता है। मूल भिन्न है ______	I. 1/10
B. 4⅓ − 3½ = ______	II. 2/5
C. 40% के तुल्य भिन्न है ______	III. 5/6
D. 0.064 ÷ (3.25 × 3.20 − 3.20 × 3.05)	IV. 2/1

नीचे दिए गए विकल्पों में से सही उत्तर चुनिए:

1. AA-II, B-III, C-IV, D-I
2. BA-III, B-II, C-IV, D-I
3. CA-IV, B-III, C-I, D-II
4. DA-IV, B-III, C-II, D-I

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: D. A-IV, B-III, C-II, D-I

Explanation

A: (1.25n)/(1.5d) = 5/3 gives (n/d) × (5/6) = 5/3, so n/d = 2/1 (A-IV). B: 13/3 − 7/2 = (26 − 21)/6 = 5/6 (B-III). C: 40% = 40/100 = 2/5 (C-II). D: denominator = 3.20 × (3.25 − 3.05) = 3.20 × 0.20 = 0.64, so 0.064 ÷ 0.64 = 0.1 = 1/10 (D-I). Hence A-IV, B-III, C-II, D-I.A: (1.25n)/(1.5d) = 5/3 से (n/d) × (5/6) = 5/3, अतः n/d = 2/1 (A-IV)। B: 13/3 − 7/2 = (26 − 21)/6 = 5/6 (B-III)। C: 40% = 40/100 = 2/5 (C-II)। D: हर = 3.20 × (3.25 − 3.05) = 3.20 × 0.20 = 0.64, अतः 0.064 ÷ 0.64 = 0.1 = 1/10 (D-I)। अतः A-IV, B-III, C-II, D-I।