Match the LIST-I with LIST-IILIST-I (Question) LIST-II (Answer) A. If x/5 = y/8, then (x + 5) : (y + 8) = ? I. 2 : 1 B. If (x : y) = 2 : 1, then (x² − y²) : (x² + y²) = ? II. 2 : 3 C. If (x² + 4y²) = 4xy, then x : y = ? III. 3 : 5 D. If A : B = 3 : 4 and B : C = 8 : 9, then A : C = ? IV. 5 : 8
Choose the correct answer from the options given below:सूची-I को सूची-II के साथ सुमेलित कीजिएसूची-I (प्रश्न) सूची-II (उत्तर) A. यदि x/5 = y/8, तो (x + 5) : (y + 8) = ? I. 2 : 1 B. यदि (x : y) = 2 : 1, तो (x² − y²) : (x² + y²) = ? II. 2 : 3 C. यदि (x² + 4y²) = 4xy, तो x : y = ? III. 3 : 5 D. यदि A : B = 3 : 4 तथा B : C = 8 : 9, तो A : C = ? IV. 5 : 8
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Correct answer: A. A-IV, B-III, C-I, D-II
Explanation
A: x = 5k, y = 8k → (5k + 5) : (8k + 8) = 5(k+1) : 8(k+1) = 5 : 8 (IV). B: x = 2, y = 1 → (4 − 1) : (4 + 1) = 3 : 5 (III). C: x² − 4xy + 4y² = 0 → (x − 2y)² = 0 → x : y = 2 : 1 (I). D: A : B : C = 24 : 32 : 36 → A : C = 24 : 36 = 2 : 3 (II). Hence A-IV, B-III, C-I, D-II.A: x = 5k, y = 8k → (5k + 5) : (8k + 8) = 5(k+1) : 8(k+1) = 5 : 8 (IV)। B: x = 2, y = 1 → (4 − 1) : (4 + 1) = 3 : 5 (III)। C: x² − 4xy + 4y² = 0 → (x − 2y)² = 0 → x : y = 2 : 1 (I)। D: A : B : C = 24 : 32 : 36 → A : C = 24 : 36 = 2 : 3 (II)। अतः A-IV, B-III, C-I, D-II।More Mathematical Reasoning and Aptitude questions
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