Match List I with List II

List I (Number Series)	List II (Value of P in the Series)
(A) 2, 9, 28, 65, 126, P, ….	(I) 220
(B) 2, 10, 30, 68, 130, P, …	(II) 222
(C) 3, 4, 11, 30, 67, 128, P, …	(III) 217
(D) 5, 12, 31, 68, 129, P, ….	(IV) 219

Choose the correct answer from the options given below:सूची-I के साथ सूची-II का मिलान कीजिए

सूची-I (संख्या शृंखला)	सूची-II (शृंखला में P का मान)
(A) 2, 9, 28, 65, 126, P, ….	(I) 220
(B) 2, 10, 30, 68, 130, P, …	(II) 222
(C) 3, 4, 11, 30, 67, 128, P, …	(III) 217
(D) 5, 12, 31, 68, 129, P, ….	(IV) 219

नीचे दिए गए विकल्पों में से सही उत्तर का चयन कीजिए:

1. A(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
2. B(A)-(IV), (B)-(II), (C)-(III), (D)-(I)
3. C(A)-(III), (B)-(II), (C)-(IV), (D)-(I)
4. D(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

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Show answer & explanation

Correct answer: C. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Explanation

All four series are built on cubes. (A) is n³ + 1 (1+1, 8+1, 27+1, …), so P = 6³ + 1 = 217 (III). (B) is n³ + n (1+1, 8+2, 27+3, …), so P = 216 + 6 = 222 (II). (C) is n³ + 3 starting from n = 0 (0+3, 1+3, 8+3, …), so P = 216 + 3 = 219 (IV). (D) is n³ + 4 (1+4, 8+4, 27+4, …), so P = 216 + 4 = 220 (I). Hence (A)-(III), (B)-(II), (C)-(IV), (D)-(I).चारों शृंखलाएँ घनों पर आधारित हैं। (A) में n³ + 1 है (1+1, 8+1, 27+1, …), अतः P = 6³ + 1 = 217 (III)। (B) में n³ + n है (1+1, 8+2, 27+3, …), अतः P = 216 + 6 = 222 (II)। (C) में n = 0 से आरंभ करते हुए n³ + 3 है (0+3, 1+3, 8+3, …), अतः P = 216 + 3 = 219 (IV)। (D) में n³ + 4 है (1+4, 8+4, 27+4, …), अतः P = 216 + 4 = 220 (I)। अतः (A)-(III), (B)-(II), (C)-(IV), (D)-(I)।