Let L and M be the sum and average of four consecutive odd numbers (a, b, c and d) respectively, and, P and Q be the sum and average of three consecutive even numbers (x, y and z) respectively. If M = Q − 6 and P = L − 16, then M =माना L और M क्रमशः चार क्रमागत विषम संख्याओं (a, b, c और d) का योग और औसत हैं, तथा P और Q क्रमशः तीन क्रमागत सम संख्याओं (x, y और z) का योग और औसत हैं। यदि M = Q − 6 और P = L − 16, तो M =

1. A32
2. B34
3. C36
4. D30

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Correct answer: B. 34

Explanation

Odd numbers a, a+2, a+4, a+6: L = 4a + 12, M = a + 3. Even numbers x, x+2, x+4: P = 3x + 6, Q = x + 2. M = Q − 6 gives x = a + 7. P = L − 16 gives 3a + 27 = 4a − 4, so a = 31 and M = 34 (check: x = 38, Q = 40 = M + 6).विषम संख्याएँ a, a+2, a+4, a+6: L = 4a + 12, M = a + 3। सम संख्याएँ x, x+2, x+4: P = 3x + 6, Q = x + 2। M = Q − 6 से x = a + 7। P = L − 16 से 3a + 27 = 4a − 4, अतः a = 31 और M = 34 (जाँच: x = 38, Q = 40 = M + 6)।