Consider the numbers a, b, c and d with values 54, 71, 75 and 99, respectively. Find a number which may be subtracted from each of them such that a/b = c/dमाना कि a, b, c और d संख्याओं के क्रमशः उनके मान 54, 71, 75 और 99 हैं। वह संख्या ज्ञात कीजिए जिसे प्रत्येक संख्या से घटाया जाए तो a/b = c/d प्राप्त हो:

1. A5
2. B2
3. C3
4. D4

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Correct answer: C. 3

Explanation

Let the number subtracted be x, so (54 − x)/(71 − x) = (75 − x)/(99 − x). Cross-multiplying: (54 − x)(99 − x) = (75 − x)(71 − x) → 5346 − 153x + x² = 5325 − 146x + x² → 21 = 7x → x = 3. Check: 51/68 = 0.75 and 72/96 = 0.75. ✓मान लीजिए घटाई जाने वाली संख्या x है, अतः (54 − x)/(71 − x) = (75 − x)/(99 − x)। तिर्यक गुणा करने पर: (54 − x)(99 − x) = (75 − x)(71 − x) → 5346 − 153x + x² = 5325 − 146x + x² → 21 = 7x → x = 3। जाँच: 51/68 = 0.75 तथा 72/96 = 0.75। ✓