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Unit 2 · Research Aptitude Paper 1 · 27 June 2025 Morning

Match the LIST-I with LIST-II
LIST-I (n = number of Trials; p = probability of Success)LIST-II (Mean of Binomial Distribution)
A. n = 16, p = 0.8I. 9.1
B. n = 21, p = 0.6II. 9.2
C. n = 13, p = 0.7III. 12.8
D. n = 23, p = 0.4IV. 12.6
Choose the correct answer from the options given below:
सूची-I को सूची-II के साथ सुमेलित कीजिए
सूची-I (n = परीक्षणों की संख्या; p = सफलता की प्रायिकता)सूची-II (द्विपद बंटन का माध्य)
A. n = 16, p = 0.8I. 9.1
B. n = 21, p = 0.6II. 9.2
C. n = 13, p = 0.7III. 12.8
D. n = 23, p = 0.4IV. 12.6
नीचे दिए गए विकल्पों में से सही उत्तर चुनिए:

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: B. A-III, B-IV, C-I, D-II

Explanation

Mean of a binomial distribution = np. A: 16 × 0.8 = 12.8 (III); B: 21 × 0.6 = 12.6 (IV); C: 13 × 0.7 = 9.1 (I); D: 23 × 0.4 = 9.2 (II). Hence A-III, B-IV, C-I, D-II.द्विपद बंटन का माध्य = np। A: 16 × 0.8 = 12.8 (III); B: 21 × 0.6 = 12.6 (IV); C: 13 × 0.7 = 9.1 (I); D: 23 × 0.4 = 9.2 (II)। अतः A-III, B-IV, C-I, D-II।

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