Match the LIST-I with LIST-IILIST-I (n = number of Trials; p = probability of Success) LIST-II (Mean of Binomial Distribution) A. n = 16, p = 0.8 I. 9.1 B. n = 21, p = 0.6 II. 9.2 C. n = 13, p = 0.7 III. 12.8 D. n = 23, p = 0.4 IV. 12.6
Choose the correct answer from the options given below:सूची-I को सूची-II के साथ सुमेलित कीजिएसूची-I (n = परीक्षणों की संख्या; p = सफलता की प्रायिकता) सूची-II (द्विपद बंटन का माध्य) A. n = 16, p = 0.8 I. 9.1 B. n = 21, p = 0.6 II. 9.2 C. n = 13, p = 0.7 III. 12.8 D. n = 23, p = 0.4 IV. 12.6
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Correct answer: B. A-III, B-IV, C-I, D-II
Explanation
Mean of a binomial distribution = np. A: 16 × 0.8 = 12.8 (III); B: 21 × 0.6 = 12.6 (IV); C: 13 × 0.7 = 9.1 (I); D: 23 × 0.4 = 9.2 (II). Hence A-III, B-IV, C-I, D-II.द्विपद बंटन का माध्य = np। A: 16 × 0.8 = 12.8 (III); B: 21 × 0.6 = 12.6 (IV); C: 13 × 0.7 = 9.1 (I); D: 23 × 0.4 = 9.2 (II)। अतः A-III, B-IV, C-I, D-II।More Research Aptitude questions
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