In a cache memory, if the address has 9 bits in the tag field and 12 bits in the index field, the sizes of main memory and cache memory would be, respectively,
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Correct answer: D. 2048K, 4K
Explanation
Main-memory address = 9 + 12 = 21 bits → 221 = 2048K words. The index addresses the cache: 212 = 4K words.More Computer System Architecture questions
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