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UGC NET · PAPER 2

UGC NET Paper 2 Computer Science – Unit 2: Computer System Architecture PYQ (September 2022)

11 questions · answer key at the end · updated 11 Oct 2026
Q3. Consider a memory system with addresses spaced at a distance of m (stride), T = bank cycle time and n = number of banks. Then the average data access time per word in a synchronous (interleaved) organisation is
  1. t = m·T/n for m ≪ n; t = T for m ≫ n
  2. t = T/n for m ≪ n; t = T for m ≫ n
  3. t = m·T for m ≪ n; t = T for m ≫ n
  4. t = m·T for m ≪ n; t = m/T for m ≫ n
Answer & explanation →
Q4. In a multiprocessor system, the crossbar switch interconnection network is an example of a
  1. Non-blocking network
  2. Blocking network
  3. Network that varies from connection to connection
  4. Recurrent network
Answer & explanation →
Q5. The representation of the 4-bit code 1101 as a 7-bit even-parity Hamming code is
  1. 1010101
  2. 1111001
  3. 1011101
  4. 1110000
Answer & explanation →
Q6. The number of gate inputs required to realise the expression ABC + AB′CD + EF′ + AD is
  1. 12
  2. 13
  3. 14
  4. 15
Answer & explanation →
Q7. Consider a logic circuit with 8 input lines (D0, D1, …, D7) and 3 output lines (A0, A1, A2) specified by:
A2 = D4 + D5 + D6 + D7
A1 = D2 + D3 + D6 + D7
A0 = D1 + D3 + D5 + D0
where + is logical OR. This circuit is a(n)
  1. 3 × 8 multiplexer
  2. Decimal to BCD converter
  3. Octal to binary encoder
  4. Priority encoder
Answer & explanation →
Q8. The total storage capacity of a floppy disk having 80 tracks and storing 128 bytes/sector is 163,840 bytes. How many sectors does this disk have (per track)?
  1. 27
  2. 2048
  3. 4K
  4. 16
Answer & explanation →
Q9. In a cache memory, if the address has 9 bits in the tag field and 12 bits in the index field, the sizes of main memory and cache memory would be, respectively,
  1. 2K, 4K
  2. 1024K, 2K
  3. 4K, 2048K
  4. 2048K, 4K
Answer & explanation →
Q50. A 4-stage pipeline has stage delays of 150, 120, 160 and 140 ns. Registers between the stages have a delay of 5 ns. Assuming a constant clocking rate, the total time required to process 1000 data items is
  1. 160.5 μs
  2. 165.5 μs
  3. 120.5 μs
  4. 590.5 μs
Answer & explanation →
Q60. Match List I with List II.
Choose the correct answer from the options given below:
List IList II
A. Stack overflowI. Software interrupt
B. TimerII. Internal interrupt
C. Invalid opcodeIII. External interrupt
D. Supervisor callIV. Machine check interrupt
  1. A-I, B-II, C-III, D-IV
  2. A-II, B-III, C-I, D-IV
  3. A-I, B-II, C-IV, D-III
  4. A-II, B-III, C-IV, D-I
Answer & explanation →
Q64. A magnetic tape drive has a transport speed of 200 inches per second and a recording density of 1600 bytes per inch. The time required to write 600000 characters of data grouped into 100-character records with a blocking factor of 10 is
  1. 1.875 sec
  2. 2.6251 sec
  3. 2.0062 sec
  4. 2.6150 sec
Answer & explanation →
Q100. Statement I: Consider the 20-bit 'branch' microinstruction format: F1 (3 bits) | F2 (3) | F3 (3) | CD (2) | BR (2) | AD (7), where F1, F2, F3 are micro-operation fields, CD = condition for branching, BR = branch field and AD = address field.
Statement II: An instruction in the above format can branch on 4 conditions.
Choose the most appropriate answer.
  1. Both Statement I and Statement II are correct
  2. Both Statement I and Statement II are incorrect
  3. Statement I is correct but Statement II is incorrect
  4. Statement I is incorrect but Statement II is correct
Answer & explanation →

Answer key

  1. 3 – A
  2. 4 – A
  3. 5 – A
  4. 6 – D
  5. 7 – C
  6. 8 – D
  7. 9 – D
  8. 50 – B
  9. 60 – D
  10. 64 – A
  11. 100 – A