Correct answer: D. A-III, B-I, C-II, D-IV
A: Q(17),N(14),K(11),H(8),E(5) decreases by 3 each time, so next = 2 = B → III. C: Z(26),U(21),Q(17),N(14),L(12) decreases by 5,4,3,2, so next = 12-1 = 11 = K → II. D: A(1),C(3),?,G(7),I(9) increases by 2 each time, so missing = 5 = E → IV. By elimination, B's missing letter must be the remaining choice, C → I. So A-III, B-I, C-II, D-IV.A: Q(17),N(14),K(11),H(8),E(5) प्रत्येक बार 3 घटता है, अतः अगला = 2 = B → III। C: Z(26),U(21),Q(17),N(14),L(12) 5,4,3,2 घटता है, अतः अगला = 12-1 = 11 = K → II। D: A(1),C(3),?,G(7),I(9) प्रत्येक बार 2 बढ़ता है, अतः लुप्त = 5 = E → IV। हटाने की प्रक्रिया से, B का लुप्त अक्षर शेष विकल्प, C → I होना चाहिए। अतः A-III, B-I, C-II, D-IV।
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