Directions (Q76–80): A machine has 16 GB main memory and a 32-bit virtual address space with 4 KB pages. Frame size equals page size.
What is the size of page table for handling the given virtual address space, given that 2 bytes each page table entry is of size ?
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: A. 2 MB
Explanation
2²⁰ entries × 2 bytes = 2 MB.
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