Directions (Q76–80): A machine has 16 GB main memory and a 32-bit virtual address space with 4 KB pages. Frame size equals page size.
If a process of size 34 KB is to be executed on this machine, what will be the size of internal fragmentation for this process?
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: D. 2 KB
Explanation
34 KB needs 9 pages = 36 KB; the last page wastes 36 − 34 = 2 KB.
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