The probability that A hits a target is 1/4 and the probability that B hits it is 2/5. Both shoot at the target. What is the probability that at least one of them hits it?
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Correct answer: D. 11/20
Explanation
P(neither hits) = (3/4)(3/5) = 9/20, so P(at least one) = 1 − 9/20 = 11/20.
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