Match List I with List II. List I: (A) ∅ ∩ {∅} = (B) {∅} ∩ {∅} = (C) {∅, {∅}} − ∅ = (D) ∅ ∪ {{∅}} =. List II: (I) ∅ (II) {∅} (III) {{∅}} (IV) {∅, {∅}}

1. A(A)-(I), (B)-(II), (C)-(III), (D)-(IV)
2. B(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
3. C(A)-(II), (B)-(I), (C)-(IV), (D)-(III)
4. D(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: D. (A)-(I), (B)-(II), (C)-(IV), (D)-(III)

Explanation

Intersecting with the empty set gives ∅. {∅} ∩ {∅} = {∅}. Removing the elements of ∅ (none) leaves {∅, {∅}}. ∅ ∪ {{∅}} = {{∅}}.