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Let G = ℝ − {0} and H = {−1, 1} be groups under multiplication. Then the map φ : G → H defined by φ(x) = x/|x| is

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Correct answer: C. An onto homomorphism, which is not one to one

Explanation

φ(x) is the sign of x, and sign(xy) = sign(x)·sign(y), so φ is a homomorphism. It hits both 1 and −1 (onto) but sends every positive number to 1 (not one-to-one).

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