The sum of all interior angles of a regular polygon of 10 sides is :10 भुजाओं वाले एक नियमित बहुभुज के सभी अन्तःकोणों का योग है :

1. A6π
2. B8π
3. C10π
4. D12π

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Correct answer: B. 8π

Explanation

Sum of interior angles of an n-sided polygon = (n − 2) × 180° = (10 − 2) × 180° = 1440°. Since 180° = π, this is 8π. The answer is 8π.n भुजाओं वाले बहुभुज के अन्तःकोणों का योग = (n − 2) × 180° = (10 − 2) × 180° = 1440°। चूँकि 180° = π, यह 8π है। उत्तर: 8π।