The population of a town increases at the rate of 5% annually. If the present population is 4410, what was it 2 years ago ?एक कस्बे की जनसंख्या 5% वार्षिक दर से बढ़ती है, यदि कस्बे की वर्तमान जनसंख्या 4410 हो, तो 2 वर्ष पहले जनसंख्या कितनी थी ?
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: C. 4000
Explanation
Let the population 2 years ago be P. Then P × (21/20)² = 4410, so P = 4410 × 400/441 = 10 × 400 = 4000.माना 2 वर्ष पहले जनसंख्या P थी। तब P × (21/20)² = 4410, अतः P = 4410 × 400/441 = 10 × 400 = 4000।More Mathematics & Numerical Ability questions
- In order to fence a square fixed 36 poles were used. If the distance between two consecutive poles is 6 meters, then the area of the square…
- If √(2n) = 64, then the value of n is :
- If M is a square number, then the next immediate square number is :
- The factors of 6 − x − 2x² are :
- If √(1 + √(1 − 2176/2401)) = 1 + x/7, then the value of x is :
- If 27x − 2/3 = 81, then value of 23x+1 is :