A number when divided by 5, 9, 13 leaves remainder 2, 6 and 10 respectively. The least such number is :

किसी संख्या को 5, 9, 13 से विभाजित करने पर क्रमश: 2, 6 तथा 10 शेष बचता है। ऐसी सबसे छोटी संख्या है :

1. A602
2. B592
3. C572
4. D582

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Correct answer: D. 582

Explanation

In each case remainder = divisor − 3, so N = LCM(5, 9, 13) − 3 = 585 − 3 = 582.

हर बार शेषफल = भाजक − 3, अतः N = LCM(5, 9, 13) − 3 = 585 − 3 = 582।