If x = (√3 + 1)/(√3 − 1) and y = (√3 − 1)/(√3 + 1), then the value of (x² + y²) is :

यदि x = (√3 + 1)/(√3 − 1) तथा y = (√3 − 1)/(√3 + 1), तो (x² + y²) का मान है :

1. A14
2. B12
3. C13
4. D16

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Correct answer: A. 14

Explanation

x = (√3 + 1)/(√3 − 1) = 2 + √3 and y = 2 − √3. x + y = 4, xy = 1, so x² + y² = 16 − 2 = 14.

x = 2 + √3, y = 2 − √3; x + y = 4, xy = 1, अतः x² + y² = 16 − 2 = 14।