Directions (Q36–40): A 3000 km long trunk operates at 1.536 Mbps and is used to transmit 64-byte frames using a sliding window protocol. The propagation delay is 6 μs/km.
The transmission and propagation delays are respectively
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Correct answer: A. Tt = 333.33 μs, Tp = 18000 μs
Explanation
Tt = 512 bits / 1.536 Mbps = 333.33 μs. Tp = 3000 × 6 = 18000 μs.More Data Communication and Computer Networks questions
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