Directions (Q36–40): A 3000 km long trunk operates at 1.536 Mbps and is used to transmit 64-byte frames using a sliding window protocol. The propagation delay is 6 μs/km.
The maximum achievable throughput (in Mbps) is
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Correct answer: C. 0.901
Explanation
Throughput = 0.587 × 1.536 Mbps ≈ 0.901 Mbps.More Data Communication and Computer Networks questions
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