Hosts P and Q are connected through a router R. The MTU of link P–R is 1500 bytes and of link R–Q is 820 bytes. A TCP segment of 1400 bytes is sent from P to Q through R with IP identification 0x1234. The IP header is 20 bytes and the DF flag is not set.
I. Two fragments are created at R and the IP datagram carrying the second fragment is 620 bytes.
II. If the second fragment is lost, R resends the fragment with IP identification 0x1234.
III. If the second fragment is lost, P is required to resend the entire TCP segment.
IV. The TCP destination port can be determined by analysing the second fragment only.
Choose the correct answer from the options given below:
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: B. I and III only
Explanation
Payload 1400 B; the 820 MTU allows 800 B of data (multiple of 8). Fragments: 800 + 20 = 820 and 600 + 20 = 620, so I is true. Routers do not retransmit (II false); TCP at P resends the whole segment (III true). The TCP header with the port is only in the first fragment (IV false).More Data Communication and Computer Networks questions
- The solution to the silly window syndrome problem is/are: I. Nagle's algorithm II. Clark's algorithm III. Jacobson's algorithm IV. Piggybac…
- Match List I with List II. Choose the correct answer from the options given below:List I List II a. CDMA I. Provides mobile internet connec…
- Arrange the following in the order of OSI layers (bottom to top): I. Transforming the raw bits into frames for transmission II. Transmissio…
- A TCP server listens on port P on host S, and a client is connected to it. While the connection is active the server crashes and reboots. T…
- Find the number of addresses in each subnet.
- Find the subnet prefix.