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UGC NET · PAPER 2

UGC NET Paper 2 Computer Science – Unit 9: Data Communication and Computer Networks PYQ (December 2022 Shift 2)

14 questions · answer key at the end · updated 11 Oct 2026
Q33. Given the Ethernet address
010110100001000101010101000110001010101000001111
in binary, what is the address in hexadecimal notation?
  1. 5A:88:AA:18:55:F0
  2. 5A:81:BA:81:AA:08
  3. 5A:18:5A:18:55:0F
  4. 5A:11:55:18:AA:0F
Answer & explanation →
Q34. A computer on a 10 Mbps network is regulated by a token bucket. The token bucket is filled at a rate of 2 Mbps. It is initially filled to capacity with 16 megabits. What is the maximum duration for which the computer can transmit at the full 10 Mbps?
  1. 1.6 seconds
  2. 2 seconds
  3. 5 seconds
  4. 8 seconds
Answer & explanation →
Q35. In standard Ethernet with a transmission rate of 10 Mbps, assume the length of the medium is 2500 m and the size of a frame is 512 bytes. The propagation speed of a signal in the cable is 2 × 108 m/s. Calculate the transmission delay and propagation delay.
  1. 25.25 μs and 51.2 μs
  2. 51.2 μs and 12.5 μs
  3. 10.24 μs and 50.12 μs
  4. 12.5 μs and 51.2 μs
Answer & explanation →
Q36. In CRC coding, if the data word is 111111, the divisor is 1010 and the remainder is 110, which of the following codewords is true?
  1. 011111101
  2. 001010110
  3. 111111110
  4. 110111111
Answer & explanation →
Q61. Hosts P and Q are connected through a router R. The MTU of link P–R is 1500 bytes and of link R–Q is 820 bytes. A TCP segment of 1400 bytes is sent from P to Q through R with IP identification 0x1234. The IP header is 20 bytes and the DF flag is not set.
I. Two fragments are created at R and the IP datagram carrying the second fragment is 620 bytes.
II. If the second fragment is lost, R resends the fragment with IP identification 0x1234.
III. If the second fragment is lost, P is required to resend the entire TCP segment.
IV. The TCP destination port can be determined by analysing the second fragment only.
Choose the correct answer from the options given below:
  1. I, II and III only
  2. I and III only
  3. III and IV only
  4. II and IV only
Answer & explanation →
Q62. The solution to the silly window syndrome problem is/are:
I. Nagle's algorithm
II. Clark's algorithm
III. Jacobson's algorithm
IV. Piggybacking algorithm
Choose the correct answer from the options given below:
  1. I and II only
  2. I and III only
  3. III and IV only
  4. II and IV only
Answer & explanation →
Q74. Match List I with List II.
Choose the correct answer from the options given below:
List IList II
a. CDMAI. Provides mobile internet connection with faster data transfer rates
b. GSMII. Allows users to connect to a network or to other devices over a wireless channel
c. UMTSIII. Access mechanism for multiple transmitters over a single channel
d. Wi-FiIV. Cellular technology employing a hybrid of FDMA and TDMA
  1. a-III, b-IV, c-II, d-I
  2. a-III, b-IV, c-I, d-II
  3. a-II, b-III, c-IV, d-I
  4. a-II, b-I, c-IV, d-III
Answer & explanation →
Q84. Arrange the following in the order of OSI layers (bottom to top):
I. Transforming the raw bits into frames for transmission
II. Transmission of raw bits over the communication channel
III. Handling user interfaces
IV. Control and monitoring of the subnet
V. Transmitting data, connection-oriented or connectionless using datagrams
Choose the correct answer from the options given below:
  1. I-II-III-IV-V
  2. II-III-IV-V-I
  3. II-I-IV-V-III
  4. I-II-IV-V-III
Answer & explanation →
Q90. A TCP server listens on port P on host S, and a client is connected to it. While the connection is active the server crashes and reboots. The client does not use the TCP keepalive timer. Which behaviour is possible?
Statement I: If the client is waiting to receive a packet, it may wait indefinitely.
Statement II: If the client sends a packet after the server reboots, it will receive a FIN segment.
  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
Answer & explanation →

Directions (Q91–95): An organisation is granted the block 130.56.0.0/16. The administrator wants to create 1024 subnets.

Q91. Find the number of addresses in each subnet.
  1. 32
  2. 64
  3. 128
  4. 16
Answer & explanation →
Q92. Find the subnet prefix.
  1. 130.56
  2. 136.0
  3. 136.255
  4. 136.56.255
Answer & explanation →
Q93. Find the first and last addresses of the first subnet.
  1. 130.56.0.0 & 130.56.254.254
  2. 130.56.0.0 & 130.56.0.63
  3. 130.0.0.0 & 130.255.255.255
  4. 130.56.0.0 & 130.56.255.63
Answer & explanation →
Q94. Find the subnet mask.
  1. 255.255.255.192
  2. 130.56.255.255
  3. 130.56.0.255
  4. 130.56.155.192
Answer & explanation →
Q95. Find the first and last addresses of the last subnet.
  1. 130.56.0.0 & 130.56.254.255
  2. 130.56.255.0 & 130.56.255.255
  3. 130.56.0.192 & 130.255.255.255
  4. 130.56.255.192 & 130.56.255.255
Answer & explanation →

Answer key

  1. 33 – D
  2. 34 – B
  3. 35 – B
  4. 36 – C
  5. 61 – B
  6. 62 – A
  7. 74 – B
  8. 84 – C
  9. 90 – C
  10. 91 – B
  11. 92 – A
  12. 93 – B
  13. 94 – A
  14. 95 – D