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What shall be the average waiting time per process if we know that 10 processes (on average) arrive every second and there are normally 20 processes in the queue?

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Correct answer: B. 02 seconds

Explanation

By Little's formula n = λ × W, where n = 20 processes in queue and λ = 10 processes/second. So W = n / λ = 20 / 10 = 2 seconds.

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