What is the total swap time (swap in + swap out) in a system for a 15 MB process with a transfer rate of 30 MBps? Given that there is an average latency of 12 ms, however no head seeks are involved.
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: A. 1.024 sec
Explanation
One transfer = 15 MB / 30 MBps = 0.5 s = 500 ms, plus 12 ms latency = 512 ms. Swap out + swap in = 2 × 512 ms = 1024 ms = 1.024 s.More System Software and Operating System questions
- Match List I with List IIList I List II A. RAID Level 2 I. Block interleaved distributed parity B. RAID Level 3 II. Also known as P+Q redun…
- Consider the following table about processes, their burst time and arrival time. Which process shall finish second last as per the respecti…
- Which of the following statements is correct for Pthreads?
- What shall be the 2nd request processed by the C-LOOK (Right) disk scheduling technique for the given request queue?
- What shall be the total head movement of cylinders for the C-SCAN disk scheduling technique if the head starts moving in the right directio…
- What shall be the 2nd request processed by the SCAN (Left) disk scheduling technique for the given request queue?