Match List - I with List - II.

1. A(a)-(III), (b)-(II), (c)-(I), (d)-(IV)
2. B(a)-(IV), (b)-(I), (c)-(II), (d)-(III)
3. C(a)-(II), (b)-(III), (c)-(IV), (d)-(I)
4. D(a)-(IV), (b)-(I), (c)-(III), (d)-(II)

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: B. (a)-(IV), (b)-(I), (c)-(II), (d)-(III)

Explanation

BCNF: every FD is implied by the candidate keys. 5NF: every join dependency is implied by them. 1NF: all domains hold atomic (scalar) values. 4NF: every MVD is implied by the keys.