Match List - I with List - II.
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Correct answer: C. A-II, B-I, C-III, D-IV
Explanation
The dual swaps + with · and 0 with 1. x·y + 0 → (x + y)·1; x̄·1 + (ȳ + z) → (x̄ + 0)·(ȳ·z); x̄·(ȳ + 0) → x̄ + ȳ·1; x·1 + (y + z̄) → (x + 0)·(y·z̄).
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