What is the total delay (latency) for a frame of 10 million bits sent on a link with 20 routers, each having a queuing time of 2 μs and a processing time of 1 μs? The link is 5000 km long, the speed of light in the link is 2 × 10⁸ m/s and the bandwidth is 6 Mbps.
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Correct answer: B. 1.691726 s
Explanation
Transmission = 10⁷ / (6 × 10⁶) ≈ 1.666667 s. Propagation = 5 × 10⁶ / (2 × 10⁸) = 0.025 s. Queuing + processing = 20 × 3 μs = 60 μs. Total ≈ 1.691727 s.More Data Communication and Computer Networks questions
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