What is the maximum bit rate of a noiseless channel with a bandwidth of 2 KHz, transmitting a signal with 8 levels?
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Correct answer: A. 12000 bps
Explanation
For a noiseless channel, the Nyquist formula gives the maximum bit rate as BitRate = 2 ×B ×log2(L), where B is the bandwidth and L is the number of signal levels. Here B = 2000 Hz and L = 8, so log2(8) = 3, giving BitRate = 2 × 2000 × 3 = 12000 bps.More Data Communication and Computer Networks questions
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