Using RSA with p = 3, q = 11 and d = 7, find the value of e and encrypt the number 19.
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Correct answer: C. 3,28
Explanation
n = 33, φ = 20. e·7 ≡ 1 (mod 20) gives e = 3. 19³ = 6859 ≡ 28 (mod 33).
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