In standard Ethernet with a transmission rate of 10 Mbps, the length of the medium is 2500 m and the frame size is 512 bits. The propagation speed of a signal in the cable is 2 × 10⁸ m/s. The transmission delay and propagation delay are
Pick an option to check yourself, or open the answer below.
Show answer & explanation
Correct answer: B. 51.2 μs and 12.5 μs
Explanation
Transmission delay = 512 bits / 10 Mbps = 51.2 μs. Propagation delay = 2500 / (2 × 10⁸) = 12.5 μs. (The original paper says '512 bytes', but the keyed values correspond to Ethernet's 512-bit minimum frame.)More Data Communication and Computer Networks questions
- How many more routers can the packet travel to?
- What is the protocol of the payload being carried by the packet?
- What is the size of the datagram?
- What is the header size?
- What is the efficiency of this datagram?
- Match List I (line-coding scheme) with List II (average bandwidth)List I List II A. NRZ-L I. B = N/4 B. 2B1Q II. B = N/8 C. 4D-PAM5 III. B…