In a Stop-and-wait system, the bandwidth of the line is 1 Mbps, and 1 bit takes 30 milliseconds to make a round trip. The bandwidth-delay product is
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Correct answer: C. 30,000 bits
Explanation
Bandwidth-delay product = bandwidth × round-trip time = 1 × 10⁶ bits/s × 30 × 10⁻³ s = 30,000 bits.More Data Communication and Computer Networks questions
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