All mock tests are FREE till 31 December — register to save your progress
Unit 8 · Theory of Computation and Compilers Paper 2 CS · December 2022 Shift 2

Directions (Q96–100): A Turing machine for the language L = {anbmcndm | n ≥ 1, m ≥ 1} is designed. The model is M = ({q0, q1, q2, q3, q4, q5, q6, q7, qf}, {a, b, c, d}, {a, b, c, d, X1, X2, Y1, Y2, B}, δ, q0, B, {qf}), and part of δ is given in the transition table below. X1 and X2 are used to mark a's and c's, and Y1 and Y2 to mark b's and d's.

abcdX1X2Y1Y2B
q0(q1, X1, R)M2
q1(q1, a, R)(q1, b, R)M1(q1, X2, R)
q2(q2, a, L)(q2, b, L)(q2, X1, R)(q2, X2, L)
q3M3(q4, Y1, R)(q6, X2, R)
q4(q4, b, R)(q5, Y2, L)M5(q4, Y2, R)
q5(q5, b, L)(q5, X2, L)M4(q5, Y2, L)
q6(q6, X2, R)(q7, Y2, R)
q7(q7, Y2, R)(qf, B, R)

What is the move in the cell numbered M2 of the table?

Pick an option to check yourself, or open the answer below.

Show answer & explanation

Correct answer: D. Error entry

Explanation

q0 is only the start state reading the first a. It never sees X1 (later a's are handled from q3), so this cell is an error entry.

More Theory of Computation and Compilers questions