Let R(ABCDEFGH) be a relation schema and F = {A → B, ABCD → E, EF → G, EF → H, ACDF → EG} the set of dependencies. The minimal cover of F is
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Correct answer: A. A → B, ACD → E, EF → G, EF → H
Explanation
B is extraneous in ABCD → E (A → B), giving ACD → E. ACDF → E follows from ACD → E, and ACDF → G follows via E and F (EF → G). Both are redundant.More Database Management Systems questions
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