Maximize z = 2x₁ + 3x₂ subject to 2x₁ + x₂ ≤ 4, x₁ + 2x₂ ≤ 5, x₁, x₂ ≥ 0. The optimum value is
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Correct answer: D. 8
Explanation
Corners: (0, 0) → 0; (2, 0) → 4; (0, 2.5) → 7.5; intersection x₁ = 1, x₂ = 2 → 2 + 6 = 8. Optimum 8.
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