If A walks 8 km South then turn right and walks 6 km and again turns North-East and walks 10 km. How far is A from the starting point ?यदि A दक्षिण दिशा में 8 किमी जाकर तब दाहिने तरफ मुड़कर 6 किमी चलता है तथा पुनः उत्तर-पूर्व दिशा में मुड़कर 10 किमी चलता है, तो A प्रारम्भिक बिन्दु से कितनी दूरी पर है ?
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Correct answer: A. 0 km0 किमी
Explanation
A goes 8 km South, then turns right (West) and goes 6 km. The straight-line distance back to the start is the hypotenuse of a 6-8-10 right triangle, which is 10 km. The third leg of 10 km is taken (loosely) as the direction back towards the start, so A ends at the starting point. Distance = 0 km. Hence the answer is 0 km.A दक्षिण में 8 किमी चलता है, फिर दाएँ (पश्चिम) मुड़कर 6 किमी चलता है। प्रारंभ बिंदु तक की सीधी दूरी 6-8-10 समकोण त्रिभुज का कर्ण अर्थात 10 किमी है। तीसरा 10 किमी का चरण (मोटे तौर पर) प्रारंभ बिंदु की ओर की दिशा माना गया है, अतः A प्रारंभ बिंदु पर ही लौट आता है। दूरी = 0 किमी। अतः उत्तर 0 किमी है।More Reasoning & Mental Ability questions
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